Question

Find out the following squares by using the identities:
$(7x+3y{)}^2$

Answer 1

We know $(a+b{)}^2=a^2+2ab+b^2$

By using this identity, we get

$(7x+3y{)}^2$

$=(7x{)}^2+(3y{)}^2+2\times 7x\times 3y$

$=49x^2+9y^2+42xy$

This is the required answer.