Question

Find out the following squares by using the identities:
${(\frac{x}{2}-\frac{y}{3})}^2$

Answer 1

We know $(a-b{)}^2=a^2+b^2-2ab$

Using this identity, we get

${(\frac{x}{2}-\frac{y}{3})}^2={\left(\frac{x}{2}\right)}^2+{\left(\frac{y}{3}\right)}^2-2\times \frac{x}{2}\times \frac{y}{3}$

$=\frac{x^2}{4}+\frac{y^2}{9}-\frac{xy}{3}$