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Ionisation Energy

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Question

Find out the ratio of energies required to remove the electrons from single electrons species of hydrogen, helium, and lithium.

A

1:4:9

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B

1:1:1

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C

1:2:3

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D

2:4:5

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Solution

The correct option is A 1:4:9
The Ionisation potential of hydrogen atom is 13.6eV.
Therefore, the change in energy involved in removing the electron from n level.
$E_{n} = - 13.6 z^{2} / n^{2}$ eV/atom
Thus, the ionisation energy ratio is 1:4:9.

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