CameraIcon

SearchIcon

MyQuestionIcon

3

You visited us 3 times! Enjoying our articles? Unlock Full Access!

Ionisation Energy

Find out the ...

Question

Find out the ratio of energies required to remove the electrons from single electrons species of hydrogen, helium, and lithium.

A

1:4:9

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B

1:1:1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

1:2:3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

2:4:5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 1:4:9
The Ionisation potential of hydrogen atom is 13.6eV.
Therefore, the change in energy involved in removing the electron from n level.
$E_{n} = - 13.6 z^{2} / n^{2}$ eV/atom
Thus, the ionisation energy ratio is 1:4:9.

Suggest Corrections

thumbs-up

0

Similar questions

Q. An energy of

24.6 e V

is required to remove one of the electrons from a neutral helium atom. The energy

(i n e V)

required to remove both the electrons from a neutral helium atom is:

24.6 eV

is required to remove one of the electrons from a neutral helium atom. The energy in

(eV)

required to remove both the electrons from a neutral helium atom is

Q. Energy required to remove one from neutral helium atom is

E_{1} e V

energy required to remove both electrons from a neutral form a neutral helium atom is

Q. The energy required to remove the electron from a singly ionized Helium atom is

2.2

times the energy required to remove an electron from Helium atom. The total energy required to ionize the Helium atom completely is:

Q. An energy of

24.6 eV

is required to remove one of the electron from a neutral helium atom. The energy

(in eV)

required to remove both the electrons from a neutral helium atom is. (integer only)

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Ionisation Energy

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Ionisation Energy

Standard IX Chemistry

Join BYJU'S Learning Program

CrossIcon