Question

Find out the wavelength of the electron orbiting in the ground state of hydrogen atom.

Answer 1

Radius of ground state of hydrogen atom

$=0.53\dot{A}=0.53\times {10}^{-10}m$

According to de Brogile relation

$2\pi r=n\lambda$

For ground state $n=1$

$2\times 3.14\times 0.53\times {10}^{-10}=1\times \lambda$

$\therefore \lambda =3.32\times {10}^{-10}m$

$=3.32\dot{A}$