Question

Find oxidation number of $Fe$ in $K_3\left[Fe\right(CN{)}_6]$.

Answer 1

In the complex $K_3\left[Fe\right(CN{)}_6]$ K(Potassium) is Alkaline metal with +1 oxidation state,then for the $K_3$ it's +3. CNis a Negative ligand ,for ${CN}_6$ it's -6

Let, oxidation state of $Fe$ will be $x$.

The total oxidation state will be zero.

$\therefore 3+x+-6=0$

$\therefore x=+3$

thus the oxidation state of $Fe$ is +3.