Find p- p3-p4-55-p-405-

p3 + p4 = 55 p + 405 ⇒4p + 3p12 = 55 p5 8 ⇒7p12 + p/5 = 47 ⇒35p + 12p60 = 47 ⇒4760p = 47 ⇒ 60 ...

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Solving Equations with Variables on Both Sides

Find p: p3+...

Question

Find p: $\frac{p}{3} + \frac{p}{4} = 55 - \frac{p + 40}{5}$ .

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Solution

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\frac{p}{3} + \frac{p}{4} = 55 - \frac{p + 40}{5}

\frac{p}{3} + \frac{p}{4} = 55 - \frac{p + 40}{5}

p

\frac{p}{4} + \frac{p}{3} = 55 - \frac{p + 40}{5}

Question 63

How much does $93 p^{2} - 55 p + 4$ exceed $13 p^{3} - 5 p^{2} + 17 p - 90 ?$

(p^{3} + q^{3}) (p - 5 q + 6 r)

p^{4} - 5 p^{3} q + 6 p^{3} r + p q^{3} + 6 p q^{3} - 5 q^{4}

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