Find the product:
$(p^{3} + q^{3}) (p - 5 q + 6 r)$ = $p^{4} - 5 p^{3} q + 6 p^{3} r + p q^{3} + 6 p q^{3} - 5 q^{4}$

True

No worries! We‘ve got your back. Try BYJU‘S free classes today!

False

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is B False
We multiply the given expressions $(p^{3} + q^{3})$ and $(p - 5 q + 6 r)$ as shown below:

$(p^{3} + q^{3}) (p - 5 q + 6 r) = p^{3} (p - 5 q + 6 r) + q^{3} (p - 5 q + 6 r) = p^{4} - 5 p^{3} q + 6 p^{3} r + q^{3} p - 5 q^{4} + 6 q^{3} r = p^{4} - 5 p^{3} q + 6 p^{3} r + q^{3} p + 6 q^{3} r - 5 q^{4}$

Hence, $(p^{3} + q^{3}) (p - 5 q + 6 r) = p^{4} - 5 p^{3} q + 6 p^{3} r + q^{3} p + 6 q^{3} r - 5 q^{4}$ .

Suggest Corrections

Similar questions

x^{2} + p x + q = 0,

If one root is square of the other root of the equation $x^{2} + p x + q = 0$ , then the relation between p and q is

(- \frac{10}{3} p q^{3}) \times (\frac{6}{5} p^{3} q)

(- \frac{10}{3} p q^{3}) \times (\frac{6}{5} p^{3} q)

(- \frac{10}{3} p q^{3}) \times (\frac{6}{5} p^{3} q)

Join BYJU'S Learning Program