Find power (in watt) supplied by current source?

-420

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Solution

The correct option is A -420
According to Tellegan's theorem,
The algebraic sum of power of each element is equal to zero.
$n \sum k = 1 V_{k} i_{k} = 0$
$P_{8 V} = V \times i$
$= - (8 \times 6)$
$= - 48 W$
$P_{4 Ω} = i^{2} R$
$= (6)^{2} \times 4$
$= 144 W$
$P_{R_{2}} = 6 \times 4 = 24 W$
$P_{3 Ω} = 10^{2} \times 3 = 300 W$
Now, From Tellegan's Theorem,
$P_{8 V} + P_{4 Ω} + P_{R_{2}} + P_{3 Ω} + P_{10 A} = 0$
$\Rightarrow - 48 W + 144 W + 24 W + 300 W = - P_{10 A}$
$\Rightarrow - P_{10 A} = 420 W \Rightarrow P_{10 A} = - 420 W$

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