Question

Find product of $-5x^{2}y,\frac{-2}{3}x{y}^{2}z,\frac{k}{15}x{y}^2$ and $\frac{-1}{4}z$ result when $x=1,y=2,z=3$

Answer 1

Product of $-5x^{2}y,\frac{-2}{3}x{y}^{2}z,\frac{k}{15}x{y}^2$ & $\frac{-1}{4}z$ is

$P=-5x^{2}y\times \frac{-2}{3}x{y}^{2}z\times \frac{k}{15}x{y}^2\times \frac{-1}{4}z$

$P=-\frac{-1}{18}{x}^4{y}^5{z}^2$

if $x=1y=2$ & $z=3$ then

$P=\frac{1}{18}\times 1\times (2{)}^5\times (3{)}^2=-2^4$

$[P=-16]$