Question

Find roots of : ${4x}^2-{4a}^{2}x(a^4-b^4)=0$.

Answer 1

Given:$4x^2-4a^{2}x(a^4-b^4)=0$

$\Rightarrow 4x[x-a^2(a^4-b^4)]=0$

$\Rightarrow 4x=0$ or $x-a^2(a^4-b^4)=0$

$\Rightarrow x=0$ or $x=a^2(a^4-b^4)$

$\therefore x=0$ or $x=a^2(a^4-b^4)$