Find solution of a pair of linear equations in two variables by elimination method
$2 x + 3 y = 0$
$3 x + 4 y = 5$

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Solution

$2 x + 3 y = 0 ⟶ (i) 3 x + 4 y = 5 ⟶ (i i)$
Multiplying $(i)$ by $3$ and $(i i)$ by $2$
$6 x + 9 y = 0 6 x + 8 y = 10$
On subtraction : $y = - 10$
putting the value of $y$ in $(i)$
$2 x + 3 (- 10) = 0$
$x = 15$

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Similar questions

3 x + 4 y = - 17

5 x + 2 y = - 19

3 x + 4 y = - 17 \to (1)

5 x + 2 y = - 19 \to (2)

Solve the following pairs of linear equations using the method of elimination by substitution

1) .2x-3y+6=0. 2x+3y-18=0

Solve the following pairs of linear (simultaneous) equations using method of elimination by substitution:

$2 x - 3 y + 6 = 0$

$2 x + 3 y - 18 = 0$

x + y = 5

2 x - 3 y = 4

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