Find nbsp-7290 - 20 - 5-343 - 216- nbsp-31-8- nbsp-21-7- nbsp-11-7- nbsp-31-7-

The correct option is B nbsp;21/7 nbsp;√(7290 × 20 × 5/343 × 216) nbsp; nbsp; nbsp;= √(729 × 10 × 20 × 5/343 ×216) nbsp; nbsp;= √(729 × 10 ...

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Byju's Answer

Standard VIII

Mathematics

Cube Root

Find nbsp;...

Question

Find $\sqrt[3]{\frac{7290 \times 20 \times 5}{343 \times 216}}$

$1 \frac{1}{7}$

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$2 \frac{1}{7}$

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$3 \frac{1}{7}$

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$3 \frac{1}{8}$

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Solution

The correct option is B
$2 \frac{1}{7}$

$\sqrt[3]{\frac{7290 \times 20 \times 5}{343 \times 216}}$

= $\sqrt[3]{\frac{729 \times 10 \times 20 \times 5}{343 \times 216}}$

= $\sqrt[3]{\frac{729 \times 1000}{343 \times 216}}$

= $\frac{\sqrt[3]{729} \times \sqrt[3]{1000}}{\sqrt[3]{343} \times \sqrt[3]{216}}$

We have $\sqrt[3]{729}$ = 9 ; $\sqrt[3]{1000}$ = 10 ; $\sqrt[3]{343}$ = 7 ; $\sqrt[3]{216}$ = 6 ;

= $\frac{9 \times 10}{7 \times 6}$

= $\frac{90}{42}$

= $\frac{15}{7}$

= $2 \frac{1}{7}$

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Similar questions

Find:

(i) (ii) (iii)

(iv) (v) (vi)

(vii) (viii)

Evaluate :

$(i) \frac{3}{7} + \frac{- 4}{9} + \frac{- 11}{7} + \frac{7}{9} (i i) \frac{2}{3} + \frac{- 4}{5} + \frac{1}{3} + \frac{2}{5} (i i i) \frac{4}{7} + 0 + \frac{- 8}{9} + \frac{- 13}{7} + \frac{17}{9} (i v) \frac{3}{8} + \frac{- 5}{12} + \frac{3}{7} + \frac{3}{12} + \frac{- 5}{8} + \frac{- 2}{7}$

Q. Find

\sqrt[3]{\frac{7290 \times 20 \times 5}{343 \times 216}}

Q. A student was asked to simplify the following

\frac{7}{5 - 2 \frac{2}{3}} \div \frac{3 - \frac{2}{3 - 1 \frac{1}{2}}}{4 - 1 \frac{1}{2}} - \frac{5}{7} \times ⎡ ⎣ \frac{7}{10} + 1 \frac{1}{5} \times \frac{3 \frac{1}{3} - 2 \frac{1}{2}}{2 \frac{5}{21} - 2} ⎤ ⎦

+ \frac{\frac{3}{1.6} + \frac{5}{3.2}}{\frac{5}{4.8} + \frac{1}{9.6}}

His answer was

3 \frac{1}{5}

Find the percentage error in the answer.

Q. Find the product:

1 \frac{1}{3} \times 3 \frac{1}{4} \times \frac{7}{8}

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Find 3√7290×20×5343×216

The correct option is B 217 3√7290×20×5343×216 = 3√729×10×20×5343×216 = 3√729×1000343×216 = 3√729×3√10003√343×3√216 We have 3√729 = 9 ; 3√1000 = 10 ; 3√343 = 7 ; 3√216 = 6 ; = 9×107×6 = 9042 = 157 = 217

Find $\sqrt[3]{\frac{7290 \times 20 \times 5}{343 \times 216}}$