Find square of the following expression
$3 a - 4 b$

a^{2} - 24 a b + 48 b^{2}

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9 a^{2} - 4 a b + 48 b^{2}

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9 a^{2} - 24 a b + 16 b^{2}

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a^{2} - 24 a b + 16 b^{2}

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Solution

The correct option is A $9 a^{2} - 24 a b + 16 b^{2}$
Squaring,
$(3 a - 4 b)^{2}$
Using, $(a - b)^{2} = a^{2} - 2 a b + b^{2}$
$= (3 a)^{2} - 2 (3 a) (4 b) + (4 b)^{2}$
$= 9 a^{2} - 24 a b + 16 b^{2}$

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Similar questions

9 a^{2} - 24 a b + 16 b^{2} - 4 x^{2}

{3 a}^{2} - 24 a b + 48 b^{2}

9 a^{2} + 16 b^{2} - 24 a b - 25 c^{2} = 0

a x + b y + c = 0

3 a - 4 b = 7

a b = 10

9 a^{2} + 16 b^{2}

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