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Question

Find sum of all 3 digit number which leaves reminder 3 when divided by 5.

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Solution

  • smallest 3 digit number which leave the remainder 3 when divided by 5 =103
    largest 3 digit number which leave the remainder 3 when divided by 5 =998
    3 digit number after 103 which leave the remainder 3 when divided by 5 =108
    an ap is formed: 103,108........998
    first term=103
    common difference=5
    let the total no. of three digit numbers which leave the remainder 3 when divided by 5=n
    998=103+(n-1)5
    180=n
    sum of ap=180/2 *(103+998)=90*1101
    =99090

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