Find sum of all 3 digit number which leaves reminder 3 when divided by 5.
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Solution
smallest 3 digit number which leave the remainder 3 when divided by 5 =103 largest 3 digit number which leave the remainder 3 when divided by 5 =998 3 digit number after 103 which leave the remainder 3 when divided by 5 =108 an ap is formed: 103,108........998 first term=103 common difference=5 let the total no. of three digit numbers which leave the remainder 3 when divided by 5=n 998=103+(n-1)5 180=n sum of ap=180/2 *(103+998)=90*1101 =99090