Question

Find the ${25}^{th}$ term from the end of the $AP:3,8,13,......,253$

Answer 1

$3,8,13,......,253$

C.D is $5$

The reverse AP is

$253,248,243,.....13,8,3$

C.D is $(-5)$

$T_{25}=253+(25-1)(-5)$

$=253-120=133$