Question

Find the additive inverse of: $7+\sqrt[4]{42}$

Answer 1

We know that the additive inverse of a number $x$ is $-x$, which when added to $x$ yields the additive identity $0$ that is

$x+(-x)=x-x=0$

Now, since

$(7+\sqrt[4]{42})+[-(7+\sqrt[4]{42}\left)\right]=7+\sqrt[4]{42}-7-\sqrt[4]{42}=0$

Hence, the additive inverse of $(7+\sqrt[4]{42})$ is $-(7+\sqrt[4]{42})$.