Question

Find the additive inverse of each of the following

(i) $\frac{1}{3}$ (ii) $\frac{23}{9}$ (iii) $-18$

(iv) $\frac{-17}{8}$ (v) $\frac{15}{-4}$ (vi) $\frac{-16}{-5}$ (vii) $\frac{-3}{11}$ (viii) $0$

(ix) $\frac{19}{-6}$ (x) $\frac{-8}{-7}$

Answer 1

We know that additive inverse of $\frac{a}{b}$ is $\frac{-a}{b}$ and of $\frac{-a}{b}$ is $\frac{a}{b}$. Therefore Additive inverse of

(i) $\frac{1}{3}$ will be $\frac{-1}{3}$

(ii) $\frac{23}{9}$ will be $\frac{-23}{9}$

(iii) -18 will be 18

(iv) $\frac{-17}{8}$ will be $\frac{17}{8}$

(v) $\frac{15}{-4}$ or $\frac{-15}{4}$ will be $\frac{15}{4}$

(vi) $\frac{-16}{-5}$ or $\frac{16}{5}$ will be $\frac{-16}{5}$

(vii) $\frac{-3}{11}$ will be $\frac{3}{11}$

(viii) 0 will be 0 ($\because$ zero has no additive inverse)

(ix) $\frac{19}{-16}$ or $\frac{-19}{6}$ will be $\frac{19}{6}$

(x) $\frac{-8}{-7}$ or $\frac{8}{7}$ will be $\frac{-8}{7}$