Question

Find the additive inverse of:
(i) $\frac{7}{-10}$
(ii) $\frac{8}{5}.$

Answer 1

(i) $\frac{7}{-10}=\frac{7\times -1}{-10\times -1}=\frac{-7}{10}$

Additive inverse of $\frac{-7}{10}\mathrm{is}\frac{7}{10}$.

(ii) Additive inverse of $\frac{8}{5}\mathrm{is}\frac{-8}{5}$.