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Question

Find the altitude of a parallelopiped determined by a,b,c if yhe base a,&b and if a=^i+^j+^k;b=2^i+4^j^k&c=^i+^j+3^k.

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Solution

Given,
a=^i+^j+^k; b=2^i+4^j^k and c=^i+^j+3^k
and the base is a parallelogram determined by a and b
The altitude of a parallelopiped is given by
h=VolumeArea of base=c(a×b)|a×b|
c(a×b)=∣ ∣113111241∣ ∣=1(14)1(12)+3(42)c(a×b)=5+3+6=4a×b=∣ ∣ ∣^i^j^k111241∣ ∣ ∣=^i(14)^j(12)+^k(42)a×b=5^i+3^j+2^ka×b=(5)2+(3)2+(2)2=25+9+4a×b=38
Hence,
h=438



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