Find the amount of nickel carbonyl produced when 60 g of carbon reacts with 242 g of carbon dioxide and 234.8 g of nickel. C+CO2→2CO Ni+4CO→Ni(CO)4
(Molar mass of nickel = 58.7 g/mol)
A
551.20 g
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B
485.60 g
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C
426.75 g
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D
861.25 g
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Solution
The correct option is C 426.75 g C+CO2→2CONi+4CO→Ni(CO)4 Moles of C = given massmolar mass=6012=5molMoles of CO2=given massmolar mass=24244=5.5mol
Finding the limiting reagent: ForC=given molesstoichiometric coefficient=51=5molForCO2=given molesstoichiometric coefficient=1.51=5.5mol
So, carbon will be the limiting reagent.
1 mol of carbon produces 2 mol of CO.
5 mol will produce 10 mol of CO.
In the second reaction, Moles of Ni=Given massMolar mass=234.858.7=4.0mol
Finding the limiting reagent: ForNi=given molesstoichiometric coefficient=41=4mol ForCO=given molesstoichiometric coefficient=104=2.5mol
Limiting reagent will be CO.
1 mole of CO produces 0.25 moles of Ni(CO)4
10 moles will produce 2.5 moles of Ni(CO)4
Mass of Ni(CO)4 produced
= 2.5×170.7=426.75g