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Question

Find the amount of nickel carbonyl produced when 60 g of carbon reacts with 242 g of carbon dioxide and 234.8 g of nickel.
C+CO22CO
Ni+4CONi(CO)4
(Molar mass of nickel = 58.7 g/mol)

A
551.20 g
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B
485.60 g
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C
426.75 g
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D
861.25 g
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Solution

The correct option is C 426.75 g
C+CO22CONi+4CONi(CO)4
Moles of C = given massmolar mass=6012=5 molMoles of CO2=given massmolar mass=24244=5.5 mol
Finding the limiting reagent:
For C=given molesstoichiometric coefficient=51=5 molFor CO2=given molesstoichiometric coefficient=1.51=5.5 mol
So, carbon will be the limiting reagent.
1 mol of carbon produces 2 mol of CO.
5 mol will produce 10 mol of CO.
In the second reaction,
Moles of Ni=Given massMolar mass=234.858.7=4.0 mol

Finding the limiting reagent:
For Ni=given molesstoichiometric coefficient=41=4 mol
For CO=given molesstoichiometric coefficient=104=2.5 mol
Limiting reagent will be CO.
1 mole of CO produces 0.25 moles of Ni(CO)4
10 moles will produce 2.5 moles of Ni(CO)4
Mass of Ni(CO)4 produced
= 2.5×170.7=426.75 g

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