wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the amount of residue obtained in grams when 2.76 g of silver carbonate is strongly heated.
(Molar mass of Ag=108 g/mol)
Ag2CO3Δ2Ag+CO2+12O2

A
2.16 g
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
2.48 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2.32 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2.64 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 2.16 g
Ag2CO3heat2Ag+CO2+12O2 Number of moles of Ag2CO3=given massmolar mass=2.76276=0.01 mol

According to stoichiometry,
1 mol of Ag2CO3 decomposes to produce 2 mol of Ag
0.01 mol of Ag2CO3 decomposes to produce 21×0.01=0.02 mol of Ag
Mass of 0.02 mol of Ag=0.02×108=2.16 g of Ag

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon