Let θ be the acute angle between the given lines, then
cos θ=∣∣b1.b2|b1||b2|∣∣
The given lines are respectively parallel to the vectors
b1=^i−^j−2^k and b2=3^i−5^j−4^k
∴ |b1|=√(1)2+(−1)2+(−2)2=√1+1+4=√6|b2|=√(3)2+(−5)2+(−4)2=√9+25+16=√50=5√2and b1.b2=(^i−^j−2^k).(3^i−5^j−4^k)=1×3−1×(−5)−2×(−4)=3+5+8=16∴ cos θ=∣∣b1.b2|b1||b2|∣∣=16√6×5√2=1610√3=85√3⇒θ=cos−1(85√3)