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Question

Find the angle between the vectors ^i^j and ^j^k.

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Solution

Let a= ^i^j+0^k and b = 0^i+^j^k

a.b=(1)(0)+(1)(1)+0(1)=1

a=1+1=2 and b=1+1=2

cos θ=a.bab=12.2=12=cosπ3

cosθ=cos(ππ3)

cosθ=cos2π3

θ=2π3
Hence, the angle between the vectors ^i^j and ^j^k is 2π3

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