Find the angle sum of all interior angles of a regular polygon which has 7 sides.

180^o

No worries! We‘ve got your back. Try BYJU‘S free classes today!

540^o

No worries! We‘ve got your back. Try BYJU‘S free classes today!

900^o

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

960^o

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
900^o

Sum of interior angle of polygon = (n - 2) × 180 $^{\circ}$

= (7 - 2) × 180 $^{\circ}$

= 900 $^{\circ}$

Suggest Corrections

Similar questions

Q. Each interior angle of a regular polygon is

144^{0}

. Find the interior angle of a regular polygon which has double the number of sides as the first polygon.

Q. Which of the following regular polygons has sum of all the interior angles as 720°?

Q. Fill in the blanks.
For a regular polygon of n sides, we have:
(i) Sum of all exterior angles = .........
(ii) Sum of all interior angles = .........

Each interior angle of a regular polygon is 144°. The measure of each interior angle of a regular polygon which has double the number of sides as the first polygon is

Q. a) What is a regular polygon of

7

sides called?
b) What is the sum of interior angles of a regular octagon?

Join BYJU'S Learning Program

Find the angle sum of all interior angles of a regular polygon which has 7 sides.

The correct option is C 900 o Sum of interior angle of polygon = (n - 2) × 180∘ = (7 - 2) × 180∘ = 900∘

The correct option is C
900^o

Sum of interior angle of polygon = (n - 2) × 180 $^{\circ}$

= (7 - 2) × 180 $^{\circ}$

= 900 $^{\circ}$