Find the angle which is equal to its complement?

45^{\circ}

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50^{\circ}

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55^{\circ}

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90^{\circ}

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Solution

The correct option is A $45^{\circ}$
Sum of complementary angles = $90^{\circ}$
Let one angle be x,
Given that its complementary is also same which is x.
$x^{\circ}$ + $x^{\circ}$ = $90^{\circ}$
2 $x^{\circ}$ = $90^{\circ}$
x = $45^{\circ}$

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Similar questions

Q. The angles of some triangles are given below. Classify each triangle acute angle, obtuse angled or right angled on the basis of its angles.
(i)

90^{\circ}, 45^{\circ}, 45^{\circ}_______________

(ii)

80^{\circ}, 60^{\circ}, 40^{\circ}_______________

(iii)

120^{\circ}, 50^{\circ}, 10^{\circ}_______________

(iv)

60^{\circ}, 60^{\circ}, 60^{\circ}_______________

(v)

92^{\circ}, 50^{\circ}, 38^{\circ}_______________

(vi)

90^{\circ}, 35^{\circ}, 55^{\circ}_______________

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Find the angle which is equal to its complement?

The correct option is A 45∘Sum of complementary angles = 90∘ Let one angle be x, Given that its complementary is also same which is x. x∘ + x∘ = 90∘ 2x∘= 90∘ x = 45∘

The correct option is A $45^{\circ}$
Sum of complementary angles = $90^{\circ}$
Let one angle be x,
Given that its complementary is also same which is x.
$x^{\circ}$ + $x^{\circ}$ = $90^{\circ}$
2 $x^{\circ}$ = $90^{\circ}$
x = $45^{\circ}$