Question

Find the angular separation between the consecutive bright fringes in a Young's double slit experiment with blue-green light of wavelength $500nm$. The separation between the slits is $2.0\times {10}^{-3}m$.

Answer 1

We know that

Angular separation $\left(\theta \right)=\frac{\beta }{D}=\frac{\lambda D}{dD}=\frac{\lambda }{d}$

Where, $\lambda \to$ wavelength to light $=5\times {10}^{-7}m$

and $d\to$ separation b/w the slits $=2\times {10}^{-3}m$

So,

$\theta =\frac{\lambda }{d}=\frac{5\times {10}^{-7}}{2\times {10}^{-3}}=2.5\times {10}^{-4}$ and $\theta =0.1414$