Find the anti-derivative (or integral) of the following by the method of inspection.
$e^{2 x} .$

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Solution

$\int e^{2 x} d x = \frac{1}{2} e^{2 x} + C (∵ \frac{d}{d x} (\frac{1}{2} e^{2 x}) = \frac{1}{2} e^{2 x} .2 = e^{2 x})$

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