Find the anti-derivative (or integral) of the following by the method of inspection.
sin 2x.

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Solution

$\int s i n 2 x d x = - \frac{1}{2} c o s 2 x + C [\begin{matrix} ∵ \frac{d}{d x} (- \frac{1}{2} c o s 2 x) = - \frac{1}{2} (- s i n 2 x) 2 = s i n 2 x \end{matrix}]$

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