Find the area and perimeter of rectangle with in length is $11 c m$ and breadth is $8 c m$

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Solution

Length $= L = 11 c m$
Breadth $B = 8 c m$
$\Rightarrow$ Area $= L \times B = 11 \times 8 = 88 c m^{2}$
Perimeter $= 2 (L + B) = 2 (11 + 8) = 38 c m$
Hence, the answer is $88 c m^{2}, 38 c m .$

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