Question

Find the area and the perimeter of a square with diagonal 24 cm.$[Take\sqrt{2}=1.41]$.

Answer 1

Length of diagonal of a square

$=\sqrt{2}s=24$cm (s$=$side length)

$\Rightarrow s=\frac{24}{\sqrt{2}}=12\sqrt{2}$cm

Area of the square$=s^2=(12\sqrt{2}{)}^2$

$=144\times 2$

$=288c{m}^2$

Perimeter of the square$=4s$

$=4\left(12\sqrt{2}\right)$

$=48\sqrt{2}$cm.