Question

Question 94

Find the area enclosed by the following figure:

Answer 1

The given shape contains a rectangle and a semi-circle.
$\therefore$ Area of rectanlge
$=l\times b=(10.2\times 1.5)c{m}^2=15.3c{m}^2$

Here, diameter of semi-circle = (10.2 - 3.9) cm = 6.3 cm

So, radius $=\frac{diameter}{2}=\frac{6.3}{2}=3.15cm$

$\therefore$ Area of semi-circle $=\frac{1}{2}\pi r^2=\frac{22}{7}\times \frac{1}{2}\times 3.15\times 3.15=15.59c{m}^2$

$\therefore$ Total area = Area of rectangle + Area of semi-circle
$=15.3+15.59=30.89c{m}^2$