Question

Question 95

Find the area enclosed by the following figure:

Answer 1

The given shape has a triangle and a rectangle.
For rectangle, l = 13 cm and b = 4 cm
$\therefore$ Area of rectangle $=l\times b=13\times 4=52c{m}^2$
For triangle, base (b) = (13 - 8) = 5 cm
and height (h) = (16 - 4) cm = 12 cm
$\therefore$ Area of triangle $=\frac{1}{2}\times b\times h=\frac{1}{2}\times 5\times 12=30c{m}^2$
$\therefore$ Total area enclosed by the shape
$=(52+30)c{m}^2=82c{m}^2$