Find the area enclosed by the following figure

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Solution

$a r e a o f Δ A B C$
$= \frac{1}{2} \cdot 2 \cdot 4$
$= 4 c m^{2}$
$a r e a o f □ A C B E = 4^{2} = 16 c m^{2}$
$T o t a l a r e a = (4 + 16) c m^{2} = 20 c m^{2} .$

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