Question

Find the area enclosed by the given figure ABCDEF as per dimensions given herewith.

Answer 1

$\mathrm{Area}\mathrm{enclosed}\mathrm{by}\mathrm{the}\mathrm{given}\mathrm{figure}=\left(\mathrm{Area}\mathrm{of}\mathrm{trapezium}\mathrm{FEDC}\right)+\left(\mathrm{Area}\mathrm{of}\mathrm{square}\mathrm{ABCF}\right)$
$$\begin{gathered} =\left[\left\{\frac{1}{2}\times \left(6+20\right)\times 8\right\}+\left(20\times 20\right)\right]{\mathrm{cm}}^2 \\ =\left(104+400\right){\mathrm{cm}}^2 \\ =504{\mathrm{cm}}^2 \end{gathered}$$

$\mathrm{Hence},\mathrm{the}\mathrm{area}\mathrm{enclosed}\mathrm{by}\mathrm{the}\mathrm{figure}\mathrm{is}504{\mathrm{cm}}^2.$