Question

Find the area of a $\Delta$ whose sides are $8m$, $17m$ and $15m.$

Answer 1

Consider the given sides.

$8m$, $17m$ and $15m$

Since, this is a triplet.

So, it is a right angle triangle.

So,

$Base=8m$

$Height=15m$

$Hypotenuse=17m$

We know that the area of the triangle

$=\frac{1}{2}\times base\times height$

Therefore,

$=\frac{1}{2}\times 8\times 15$

$=60m^2$

Hence, this is the answer.