Find the area of a rhombus whose side is $5 c m$ and whose altitude is $4.8 c m$ . If one of its diagonal is $8 c m$ long, find the length of the other diagonal.

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Solution

Area of rhombus $=$ Base $\times$ Height $= \frac{1}{2} \times Product of diagonals$

$\Rightarrow 5 \times 4.8 = \frac{1}{2} \times (8 \times x)$

$\Rightarrow 24 = \frac{1}{2} \times (8 \times x)$

$\Rightarrow x = 6$ cm

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Find the area of a rhombus whose side is 5 cm and whose altitude is 4.8 cm. If one of its diagonal is 8 cm long, find the length of the other diagonal.

Area of rhombus = Base × Height =12×Product of diagonals⇒5×4.8=12×(8×x)⇒24=12×(8×x)⇒x=6 cm

Find the area of a rhombus whose side is $5 c m$ and whose altitude is $4.8 c m$ . If one of its diagonal is $8 c m$ long, find the length of the other diagonal.

Area of rhombus $=$ Base $\times$ Height $= \frac{1}{2} \times Product of diagonals$

$\Rightarrow 5 \times 4.8 = \frac{1}{2} \times (8 \times x)$

$\Rightarrow 24 = \frac{1}{2} \times (8 \times x)$

$\Rightarrow x = 6$ cm