Question

Find the area of a right triangle whose base is 1.2 m and hypotenuse 3.7 m.

Answer 1

Here, base = 1.2 m and hypotenuse = 3.7 m

In the right angled triangle:

Perpendicular = $\sqrt{(H\mathrm{ypotenuse}{)}^2-(B\mathrm{ase}{)}^2}$

$$\begin{gathered} =\sqrt{{\left(3.7\right)}^2-{\left(1.2\right)}^2} \\ =\sqrt{13.69-1.44} \\ =\sqrt{12.25} \\ =3.5 \end{gathered}$$
Area = $\left(\frac{1}{2}\times \mathrm{base}\times \mathrm{perpendicular}\right)$ sq. units
= $\left(\frac{1}{2}\times 1.2\times 3.5\right)$ m²
∴ Area of the right angled triangle = 2.1 m²