Question

Find the area of a sector of a circle with radius $6$cm if angle of the sector is ${60}^o$.

Answer 1

Area of sector$=\frac{\theta }{{360}^o}\times \pi r^2$ where $\theta ={60}^o$

$r=6$cm

$\Rightarrow \frac{{60}^o}{{360}^o}\times \pi \times 6\times 6=\frac{1}{6}\times \frac{22}{7}\times 36=\frac{22}{7}\times 6$

$=\frac{132}{7}c{m}^2$.