Question

Find the area of a sector of a circle with radius $6cm$ if angle of the sector is ${60}^o$.

Answer 1

$Radiusofasectorofacircle,$ $r=6cm$.
$Angleofasectorofacircle,$ $\theta ={60}^o$
$Areaofasectorofacircle=?$
$Areaofasectorofacircle$ $=\frac{\theta }{360}\times \pi r^2$
$=\frac{60}{360}\times \frac{22}{7}\times (6{)}^2$
$=\frac{1}{6}\times \frac{22}{7}\times {36}^o$
$=\frac{132}{7}$
$=18.8sq.cm.$