Question

Find the area of a sector of a circle with radius 6 cm if angle of the sector is ${60}^{\circ }$.

Answer 1

Area of the sector making angle $\theta =\left(\frac{\theta }{{360}^{\circ }}\right)\times \pi r^2$
Area of the sector making angle ${60}^{\circ }=\frac{({60}^{\circ }}{{360}^{\circ }})\times \pi r^{2}c{m}^2$
$=\left(\frac{1}{6}\right)\times 6^2\pi =\frac{36}{6}\pi c{m}^2=6\times \frac{22}{7}c{m}^2=\frac{132}{7}c{m}^2$
[1 mark]