Question

Find the area of a sector of a circle with radius $6cm$ if angle of the sector is ${60}^{°}$

Answer 1

Solve for area of sector

Given,

1. Radius $r=6cm$
2. Angle of the sector $\theta ={60}^{°}$

We know that,

Area of the sector$=\frac{\theta }{360}\pi r^2$

$$\begin{gathered} =\frac{60}{360}\times \frac{22}{7}\times 6\times 6 \\ =\frac{132}{7}c{m}^2 \\ =18.86c{m}^2 \end{gathered}$$

Hence, area of a sector of a circle is $18.86c{m}^2$