Question

Find the area of a sector with radius 6 cm with angle of the sector is ${60}^0$

Answer 1

Area of sector

$=\frac{x}{{360}^o}\times \pi r^2$

$=\frac{{60}^o}{{360}^o}\times \pi (6{)}^2$

$=\frac{1}{6}\times \pi (6{)}^2$

$=6\pi c{m}^2$.