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Question

Find the area of  a square inscribed in a circle of radius $$a$$
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Solution

$$Radius$$ $$=a$$ & $$Diameter$$ $$=2a$$
$$Diagonal\space of\space square$$ $$=2a$$
$$AC^2=AB^2+BC^2$$
$$(2a)^2=(side)^2 + (side)^2$$
$$4a^2=2 side^2$$
$$side^2=\dfrac{4 a^2}{2}=2a^2$$
$$Area\space of\space square$$ $$=side^{2}=2a^{2}$$

Mathematics

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