Question

find the area of a square whose perimeter is 260.8 m.

Answer 1

$$\begin{gathered} \mathrm{Perimeter}\mathrm{of}\mathrm{square}=4\times \mathrm{side}=260.8\mathrm{m} \\ \mathrm{side}=\frac{260.8\mathrm{m}}{4}=65.2\mathrm{m} \\ \mathrm{So}\mathrm{area}\mathrm{of}\mathrm{square}={\left(\mathrm{side}\right)}^2=65.2\times 65.2 \\ =4251.04{\mathrm{m}}^2 \end{gathered}$$