Find the area of a trapezium when :
Its parallel sides are $16 c m$ and $22 c m,$ and the perpendicular distance between them is $11 c m .$

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Solution

Here, $a = 16$
$b = 22$
$h = 11$
Area of trapezium $= [\frac{a + b}{2}] \times h$
$= \frac{16 + 22}{2} \times 11$
$= \frac{38}{2} \times 11$
$= 19 \times 11$
$= 209.$

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Find the area of a trapezium when : Its parallel sides are 16cm and 22cm, and the perpendicular distance between them is 11cm.

Here,a=16b=22h=11Area of trapezium =[a+b2]×h=16+222×11=382×11=19×11=209.

Find the area of a trapezium when :
Its parallel sides are $16 c m$ and $22 c m,$ and the perpendicular distance between them is $11 c m .$

Here, $a = 16$
$b = 22$
$h = 11$
Area of trapezium $= [\frac{a + b}{2}] \times h$
$= \frac{16 + 22}{2} \times 11$
$= \frac{38}{2} \times 11$
$= 19 \times 11$
$= 209.$