Question

Find the area of a trapezium whose parallel sides are 32 cm and 27 cm, and the distance between them is 15 cm.

Answer 1

The parallel sides of the trapezium are a = 32 cm, b = 27 cm
h = 15 cm
$\text{Area of trapezium}=\frac{1}{2}(a+b)h$
$=\frac{1}{2}(32+27)15$
$=\frac{1}{2}\left(59\right)15=442.5{\text{cm}}^2$
Therefore, the area of a trapezium is 481 cm${}^2.$