Find the area of a trapezium whose parallel sides are 9 cm and 6 cm respectively and the distance between these sides is 8 cm.

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Solution

ar(trapezium) = $\frac{1}{2}$ ⨯ (sum of parallel sides) ⨯ (distance between them)
= $\frac{1}{2}$ ⨯ (9 + 6) ⨯ 8
= 60 cm²
Hence, the area of the trapezium is 60 cm².

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The parallel sides of a trapezium are 12 cm and 9 cm and the diatance between them is 8 cm. Find the area of the trapezium.

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Find the area of a trapezium whose parallel sides are 9 cm and 6 cm respectively and the distance between these sides is 8 cm.

ar(trapezium) = 12 ⨯ (sum of parallel sides) ⨯ (distance between them) = 12 ⨯ (9 + 6) ⨯ 8 = 60 cm2 Hence, the area of the trapezium is 60 cm2.

ar(trapezium) = $\frac{1}{2}$ ⨯ (sum of parallel sides) ⨯ (distance between them)
= $\frac{1}{2}$ ⨯ (9 + 6) ⨯ 8
= 60 cm²
Hence, the area of the trapezium is 60 cm².