Question

Find the area of a trapezium whose parallel sides are of length 10 cm and 6 cm respectively and the perpendicular distance between the two parallel sides is 4.5 cm. ( in $c{m}^2$)

Answer 1

Area of trapezium = $\frac{1}{2}$ (Sum of parallel sides $\times$ Distance between them)
$\therefore$ Area = $\frac{1}{2}(10+6)\times 4.5c{m}^2$
= $\frac{1}{2}\times 16\times 4.5c{m}^2$
= 36 $c{m}^2$
Hence, the area of the given trapezium is 36 $c{m}^2$