Question

Find the area of a trapezium whose parallel sides are of length 16 dm and 22 dm and whose height is 12 dm.

Answer 1

$$\begin{gathered} \text{Given:} \\ \text{Lengths of the parallel sides are 16 dm and 22 dm.} \\ \text{And, height between the parallel sides is 12 dm.} \\ \text{Area of trapezium =}\frac{1}{2}\text{×(Sum of the parallel sides)×(Height)} \\ =\frac{1}{2}\times (16+22)\times \left(12\right) \\ {\text{=228 dm}}^2 \\ =228\times \text{dm×dm} \\ \text{=228×}\frac{1}{10}\text{m×}\frac{1}{10}\text{m} \\ =2.28{\text{m}}^2 \end{gathered}$$