Question

Find the height of a trapezium, the sum of the lengths of whose bases (parallel sides) is 60 cm and whose area is 600 cm².

Answer 1

$$\begin{gathered} \text{Given:} \\ \text{Sum of the parallel sides of a trapezium = 60 cm} \\ {\text{Area of the trapezium = 600 cm}}^2 \\ \text{Area of trapezium=}\frac{1}{2}\text{×(Sum of the parallel sides)×(Height)} \\ \mathrm{On}\mathrm{putting}\mathrm{the}\mathrm{values}: \\ 600=\frac{1}{2}\times 60\times \text{(Height)} \\ 600=30\times \text{(Height)} \\ \text{Height =}\frac{600}{30}\text{= 20 cm} \end{gathered}$$